G(-1/3)=2x^2-3x+1

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Solution for G(-1/3)=2x^2-3x+1 equation: 



(-1/3)=2G^2-3G+1

We move all terms to the left:

(-1/3)-(2G^2-3G+1)=0

We get rid of parentheses

-2G^2+3G-1-1/3=0

We multiply all the terms by the denominator


-2G^2*3+3G*3-1-1*3=0

We add all the numbers together, and all the variables

-2G^2*3+3G*3-4=0

Wy multiply elements

-6G^2+9G-4=0

a = -6; b = 9; c = -4;
Δ = b2-4ac
Δ = 92-4·(-6)·(-4)
Δ = -15
Delta is less than zero, so there is no solution for the equation

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